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Noncentral chi-square distribution
   
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Noncentral chi-square
Probability density function
Cumulative distribution function
Parameters k > 0\, degrees of freedom

\lambda > 0\, non-centrality parameter

Support x \in [0; +\infty)\,
Probability density function (pdf) \frac{1}{2}e^{-(x+\lambda)/2}\left (\frac{x}{\lambda} \right)^{k/4-1/2}
 I_{k/2-1}(\sqrt{\lambda x})
Cumulative distribution function (cdf)  :\sum_{j=0}^\infty e^{-\lambda/2} \frac{(\lambda/2)^j}{j!} \frac{\gamma(j+k/2,x/2)}{\Gamma(j+k/2)}\,
Mean k+\lambda\,
Median
Mode
Variance 2(k+2\lambda)\,
Skewness \frac{2^{3/2}(k+3\lambda)}{(k+2\lambda)^{3/2}}
Excess kurtosis \frac{12(k+4\lambda)}{(k+2\lambda)^2}
Entropy
Moment-generating function (mgf) \frac{\exp\left(\frac{ \lambda t}{1-2t }\right)}{(1-2 t)^{k/2}} for 2t < 1
Characteristic function \frac{\exp\left(\frac{i\lambda t}{1-2it}\right)}{(1-2it)^{k/2}}

In probability theory and statistics, the noncentral chi-square or noncentral ?2 distribution is a generalization of the chi-square distribution. If Xi are k independent, normally distributed random variables with means µi and variances \sigma_i^2, then the random variable

\sum_{i=1}^k \left(\frac{X_i}{\sigma_i}\right)^2

is distributed according to the noncentral chi-square distribution. The noncentral chi-square distribution has two parameters: k which specifies the number of degrees of freedom (i.e. the number of Xi), and ? which is related to the mean of the random variables Xi by:

\lambda=\sum_{i=1}^k \left(\frac{\mu_i}{\sigma_i}\right)^2.

Note that some references define ? as one half of the above sum.

Contents

Properties

The probability density function is given by


f_X(x; k,\lambda) = \sum_{i=0}^\infty \frac{e^{-\lambda/2} (\lambda/2)^i}{i!} f_{Y_{k+2i}}(x),

where Yq is distributed as chi-square with q degrees of freedom.

From this representation, the noncentral chi-squared distribution is seen to be a Poisson-weighted mixture of central chi-squared distributions. Suppose that a random variable J has a Poisson distribution with mean ? / 2, and the conditional distribution of Z given J = j is chi-squared with k+2i degrees of freedom. Then the unconditional distribution of Z is non-central chi-squared with k degrees of freedom, and non-centrality parameter ?.

Alternatively, the pdf can be written as

f_X(x;k,\lambda)=\frac{1}{2} e^{-(x+\lambda)/2} \left (\frac{x}{\lambda}\right)^{k/4-1/2} I_{k/2-1}(\sqrt{\lambda x})

where I?(z) is a modified Bessel function of the first kind given by

 I_a(y) := (y/2)^a \sum_{j=0}^\infty \frac{ (y^2/4)^j}{j! \Gamma(a+j+1)}

The moment generating function is given by

M(t;k,\lambda)=\frac{\exp\left(\frac{ \lambda t}{1-2t }\right)}{(1-2 t)^{k/2}}.

The first few raw moments are:

\mu^'_1=k+\lambda
\mu^'_2=(k+\lambda)^2 + 2(k + 2\lambda)
\mu^'_3=(k+\lambda)^3 + 6(k+\lambda)(k+2\lambda)+8(k+3\lambda)
\mu^'_4=(k+\lambda)^4+12(k+\lambda)^2(k+2\lambda)+4(11k^2+44k\lambda+36\lambda^2)+48(k+4\lambda)

The first few central moments are:

\mu_2=2(k+2\lambda)\,
\mu_3=8(k+3\lambda)\,
\mu_4=12(k+2\lambda)^2+48(k+4\lambda)\,

The nth cumulant is

K_n=2^{n-1}(n-1)!(k+n\lambda).\,

Hence

\mu^'_n = 2^{n-1}(n-1)!(k+n\lambda)+\sum_{j=1}^{n-1} \frac{(n-1)!2^{j-1}}{(n-j)!}(k+j\lambda )\mu^'_{n-j}.

Again using the relation between the central and noncentral chi-square distributions, the cumulative distribution function (cdf) can be written as

P(x; k, \lambda ) = \sum_{j=0}^\infty e^{-\lambda/2} \frac{(\lambda/2)^j}{j!} Q(x; k+2j)

where Q(x;k) is the cumulative distribution function of the central chi-squared distribution which is given by

Q(x;k)=\frac{\gamma(k/2,x/2)}{\Gamma(k/2)}\,

where ?(k,z) is the lower incomplete Gamma function.

Derivation of the pdf

The derivation of the probability density function is most easily done by performing the following steps:

  1. First, assume without loss of generality that \sigma_1=\ldots=\sigma_k=1. Then the joint distribution of X_1,\ldots,X_k is spherically symmetric, up to a location shift.
  2. The spherical symmetry then implies that the distribution of X=X_1^2+\ldots+X_k^2 depends on the means only through the squared length, \lambda=\mu_1^2+\ldots+\mu_k^2. Without loss of generality, we can therefore take \mu_1=\sqrt{\lambda} and \mu_2=\dots=\mu_k=0.
  3. Now derive the density of X=X_1^2 (i.e. k=1 case). Simple transformation of random variables shows that :\begin{align}f_X(x,1,\lambda) &= \frac{1}{2\sqrt{x}}\left( \phi(\sqrt{x}-\sqrt{\lambda}) + \phi(\sqrt{x}+\sqrt{\lambda}) \right )\\ &= \frac{1}{\sqrt{2\pi x}} e^{-(x+\lambda)/2} \cosh(\sqrt{\lambda x}),\\ \end{align}
    where \phi(\cdot) is the standard normal density.
  4. Expand the cosh term in a Taylor series. This gives the Poisson-weighted mixture representation of the density, still for k=1. The indices on the chi-squared random variables in the series above are 1+2i in this case.
  5. Finally, for the general case. We've assumed, wlog, that X_2,\ldots,X_k are standard normal, and so X_2^2+\ldots+X_k^2 has a central chi-squared distribution with (k-1) degrees of freedom, independent of X_1^2. Using the poisson-weighted mixture representation for X_1^2, and the fact that the sum of chi-squared random variables is also chi-squared, completes the result. The indices in the series are (1+2i)+(k-1) = k+2i as required.

Related distributions

  • If V is chi-square distributed V \sim \chi_k^2 then V is also non-central chi-square distributed: V \sim {\chi'}^2_k(0)
  • If J \sim Poisson(\frac{\lambda}{2}), then \chi_{k+2J}^2 \sim {\chi'}_k^2(\lambda)
Various chi and chi-square distributions
Name Statistic
chi-square distribution \sum_1^k \left(\frac{X_i-\mu_i}{\sigma_i}\right)^2
noncentral chi-square distribution \sum_1^k \left(\frac{X_i}{\sigma_i}\right)^2
chi distribution \sqrt{\sum_1^k \left(\frac{X_i-\mu_i}{\sigma_i}\right)^2}
noncentral chi distribution \sqrt{\sum_1^k \left(\frac{X_i}{\sigma_i}\right)^2}

Software and online calculator

Many statistical software packages and libraries include functions for computing noncentral chisquare densities and probabilities. The table below gives commands for the following example problems:

  1. Density fX(x;k,?) with x=5.0, k=3, ? = 1.5
  2. Cumulative probability P(x;k,?) with x=5.0, k=3, ? = 1.5
  3. Quantile: Find x in P(x;k,?) = q with k=3, ? = 1.5, q=0.5
  4. Critical noncentral parameter: Find ? in P(x;k,?) = q with x=5.0,k=3, and q=0.5
  5. Random numbers: Generate 100 random observations from the distribution with k=3, ?=1.5
Software Density Cumulative Prob. Quantile Noncentral parameter Random numbers
Matlab ncx2pdf(5.0,3,1.5) ncx2cdf(5.0,3,1.5) ncx2inv(.5,3,1.5) fsolve(@(L)(ncx2cdf(5.0,3,L)-.5), 1) ncx2rnd(3,1.5,100,1)
R dchisq(5.0,3,1.5) pchisq(5.0,3,1.5) qchisq(.5,3,1.5) require(MBESS);

conf.limits.nc.chisq( 5,NULL,3,0,.5)

rchisq(100,3,1.5)
SAS PROBCHI(5.0,3,1.5) CDF('CHISQUARE',5.0,3,1.5) CINV(.5,3,1.5) CNONCT(5.0,3,.55)  ?
Stattab [1] NA 5.0 3 1.5 ? .  ? 3 1.5 0.5 .  ? NA
Correct Answer 0.097257 0.649285 3.668745 2.898530 Varies

Note: Any software that produces the answers 0.101384, 0.490071, 5.09848 for the first three problems is including a factor of 0.5 in the definition of the noncentrality parameter. This is standard in statistics texts (e.g. [2]), but apparently not among programmers who don't read before writing their code.

These parameters can also be calculated online.

References

  1. ^ MD Anderson Cancer Center [1]
  2. ^ R. Christensen, Plane Answers to Complex Questions (3rd edition, 2002), Springer, NY, p.424.
  • Abramowitz, M. and Stegun, I.A. (1972), Handbook of Mathematical Functions, Dover. Section 26.4.25.
  • Johnson, N. L. and Kotz, S., (1970), Continuous Univariate Distributions, vol. 2, Houghton-Mifflin.


Index Of Related Pages




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